(2x)/(x^2-9)-1/(x-3)

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Solution for (2x)/(x^2-9)-1/(x-3) equation: 


D( x )

x-3 = 0

x^2-9 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x^2-9 = 0

x^2-9 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

(2*x)/(x^2-9)-(1/(x-3)) = 0

(2*x)/(x^2-9)-(x-3)^-1 = 0

(2*x)/(x^2-9)-1/(x-3) = 0

(2*x*(x-3))/((x^2-9)*(x-3))+(-1*(x^2-9))/((x^2-9)*(x-3)) = 0

2*x*(x-3)-1*(x^2-9) = 0

x^2-6*x+9 = 0

x^2-6*x+9 = 0

x^2-6*x+9 = 0

DELTA = (-6)^2-(1*4*9)

DELTA = 0

x = 6/(1*2)

x = 3 or x = 3

(x-3)^2 = 0

((x-3)^2)/((x^2-9)*(x-3)) = 0

((x-3)^2)/((x^2-9)*(x-3)) = 0 // * (x^2-9)*(x-3)

(x-3)^2 = 0

x-3 = 0 // + 3

x = 3

x in { 3} 

x belongs to the empty set

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